How much CaCO3 could be decomposed by 90 000 kj of heat energy?
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Heya
DELTA H = (delta H of products) - (delta H of reactants) =
W. K. T
CaO +CO2---> CaCO3 and decomposition reaction
CaCO3 - - > CaO + CO2
((1 mole CaO)(-636.6 kJ/mole) + (1 mole CO2)(-393.5 kJ/mole)) - (1 mole CaCO3)(-1206.9 kJ/mole) = -1030.1 kJ - (-1206.9 kJ) = +176.8 kJ
HOPE IT HELPS YOU ALL☺️
DELTA H = (delta H of products) - (delta H of reactants) =
W. K. T
CaO +CO2---> CaCO3 and decomposition reaction
CaCO3 - - > CaO + CO2
((1 mole CaO)(-636.6 kJ/mole) + (1 mole CO2)(-393.5 kJ/mole)) - (1 mole CaCO3)(-1206.9 kJ/mole) = -1030.1 kJ - (-1206.9 kJ) = +176.8 kJ
HOPE IT HELPS YOU ALL☺️
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