How much calcium can be obtained from 1 mol of fluorapatite?
10 mol
6 mol
4 mol
2 mol
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Several moles of calcium that can be obtained from 1 mol of fluorapatite is 10 mol.
- The formula of fluorapatite is Ca5(PO4)3F.
- The reaction of Ca5(PO4)3F with sulphuric acid gives a total of 10 moles of calcium.
- The reaction of fluorapatite is 2Ca5(PO4)3F + 7H2SO4 -------> 2HF + 3Ca(H2PO4)2 + 7CaSO4.
- So, 7 calcium from CaSO4 and 3 calcium from Ca(H2PO4)2 are obtained in the reaction.
- So, 1 mole of fluorapatite reacts with 7 moles of sulphuric acid to give a total of 10 moles he calcium.
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