Question

How much calcium carbonate is needed to produce enough CO2 which measure 44.8 L at NTP?
(A) 150 g
(B) 2 mole
(C) 6.022 x 10^22 molecules
(D) 1g-molecule
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Answer 1

Answer:

2 moles

At NTP one mole gas has 22.4 L volume . 44.8 means 2 mole CO2 .

Answer 2

Answer:

Option B

Explanation:

1 mole CO2 occupies 22.4 L volume at NTP

So 44.8 L implies 2 mole CO2

By stoichiometry,

2 mole CaCO3 is required to produce 2 mole CO2