Question

How much Calcium is in the amount of Ca(NO3)2 that contains 20.0g of Nitrogen?

Answer 1

Answer:

• One molecule of Ca(NO3)2 contains 2 atoms of N. One molecule of Ca(NO3)2 contains 2 atoms of N. 0.71 mole Ca(NO3)2 = 40 x 0.71 = 28.4 g Ca.

Explanation:

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Answer 2

Answer:

One molecule of Ca(NO3)2 contains 2 atoms of N. One molecule of Ca(NO3)2 contains 2 atoms of N. 0.71 mole Ca(NO3)2 = 40 x 0.71 = 28.4 g Ca.

Explanation:

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