Question

How much calcium is in the amounts of Ca(NO3)2 that contains 20g of nitrogen

Answer 1

Answer 28.571g

explanation -

2 mole of N = 1 mole of Ca

28g N = 40g Ca

so let for 20g of N xg of Ca is needed so

by unitry method

.

x=(40*20)\28

x= 28.571g