Question

How much calcium is present in ca(no3)2 that contain 1.4g nitrogen?

Answer 1

Answer:

One molecule of Ca(NO3)2 contains 2 atoms of N.

Mass of nitrogen in one mole Ca(NO3)2 molecule = 28 g ( 2 x molar mass of nitrogen)

28g N = one mole molecule of Ca(NO3)2.

20 g N = 1x 20 /28 = 0.71 mole of Ca(NO3)2.

One molecule of Ca(NO3)2 contains 2 atoms of N.

1 mole Ca(NO3)2 = 40 g Ca

0.71 mole Ca(NO3)2 = 40 x 0.71 = 28.4 g Ca.

Answer 2

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Answer in Attachment...