English, asked by gaganghuman2004, 10 months ago

how much calclum carbonate is required to produce 100l carbondioxide at STP ? caco3 --> cao+co2

Answers

Answered by tsradhanjali3

1

Answer:

10,000/22.4

Explanation:

22.4l of CO2=100g of CaCO3

1l of CO2=100/22.4g of CaCO3

100l of CO2=10000/22.4g of CaCO3

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