Question

How much calium is present in the total amount of ca(no3)2 that contains 20g oog nitrogen?

Answer 1

Explanation:

One molecule of Ca(NO3)2 contains 2 atoms of N. One molecule of Ca(NO3)2 contains 2 atoms of N. 0.71 mole Ca(NO3)2 = 40 x 0.71 = 28.4 g Ca.

Answer 2

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One molecule of Ca(NO3)2 contains 2 atoms of N. One molecule of Ca(NO3)2 contains 2 atoms of N. 0.71 mole Ca(NO3)2 = 40 x 0.71 = 28.4 g Ca

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