Question

how much calories of heat are needed to melt 80 g of ice at 0 degrees C ? latent heat of fusion of ice = 80 calories/ g​

Answer 1

Explanation:

We know,

Kf(H2O)=ΔHfusionm×1000RTf2Msolvent

                   =80×18×10002×(273.15)2×18

                   =80×10002×74610.9

                    =1.865K.Kg/mol

Tf′=0oC−iKf.m

      =0−(1.95)(1.865)(0.57.45/74.5)

      =−0.73oC