Question

How much CaO is to
be added to the
furnace charge for
each 1280 kg of pure
CaC2,
produced?​

Answer 1

56 gCaO forms =64 g CaC

2

0%=

56

x

×100

x=

100

20×56

=11.2 g

CaO+C

2

→CaC

2

+CO

2

↑

(50+x) 36 g 64 g

Initial man of reactab =(56+x)+36=92+x

final man will be =64+x

20%=

64+x

x

×100

1280+20x=100x

x=

80

1280

=16 g

∴ for one mole of CaO(56 g) we have 16 gCaO extra

20%=

1280+y

y

×100

256+0.2y=y

y=

0.8

252

=320 kg

Mole of CaC

2

=

64

1280×10

3

=20 mole

Mole of CaO=20

Mass of CaO=20×52=1120 g

Total mass of CaO=1120+320=1440 kg

Option b

Explanation:

I hope u r understand