Question

how much carbon disulphide will be formed if 4 gram of carbon was heated with 8 gram of sulphur also identify the limiting reagent​

Answer 1

Explanation:

B. 79.2%

C+2S→CS2

Ideally, 1 mole of C will react with 2 moles of S to form CS2

1 mol of C = 12g 1 mol of S = 32g

12g carbon reacts with = 64g of Sulphur 1g carbon reacts with = 6412g of Sulphur

4g carbon reacts with = 6412×4=643g of Sulphur

But we have only 8g of sulphur

It mean sulphur is limiting agent.

due to sulphur is limiting reagent reaction will proceed according to sulphur .

64g sulphur formed = 76g CS2

1g S formed= 7664 g CS2

8g S formed = 7664×8=9.5g CS2

Hence, % purity =Wt. of productWt. of reactants×100 = 9.5(4+8)×100=9.512×100

= 79.16 % = 79.2 %