Question

How much charge flows from a 12.0 V battery when it is connected to a 9 x 10^-6 Farad capacitor? (express your answer as a decimal with no units)

Answer 1

In case of capacitor charge is given by the formula

q= CV

So q =( 9×10^-6)× 12

= 108 ×10^-6 coulomb.

Answer 2

Answer:

The charge that flows from a battery is equal to    $1.08\times10^{-4} C$.

Explanation:

Given:

Q = $9\times10^{-6} F$

V = 12V

Here,

The charge is denoted by Q.

The voltage is denoted by V.

The Capacitor is denoted by C.

Now,

By the equation,

Q = CV

Q = $9\times 10^{-6} \times12$

Q = $1.08\times10^{-4} C$

So, the charge that flows from a battery is equal to    $1.08\times10^{-4} C$.