Question

How much charge in 1 kg of electron?​

Answer 1

Charge on 9.1×10^-31 kg of e- = -1.6 × 10^-19

Thus, charge on 1Kg of electron = (-1.6×10^-19)/(9.1×10^-31)

$= \frac{ - 1.6 \times {10}^{ - 19} }{9.1 \times {10}^{ - 31} }$

$= \frac{ - 16}{91} \times {10}^{ - 19 + 31}$

$= -0.176 \times {10}^{12} C$

$= -1.76 \times {10}^{11} C$

Answer 2

Given that,

1 kg of electron.

To find,

What is the amount of charge possessed by 1 kg of electron?

Solution,

Charge on 1 kg of electrons, q = ne

Charge of an electron = 1.602 * 10^-19 C

Mass of an electron = 9.11 * 10^-31 kg

Electrons in 1kg = 1/(9.11 * 10^-31) = 1.10 * 10^30.

Charge of 1kg of electrons = (1.10 * 10^30)(-1.602 * 10^-19) =

-1.76 * 10^11 C

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