Chemistry, asked by kumarshreeja77, 8 months ago

How much charge in Faradays is required for the reduction of 5 mol of Ca+2 to Ca?
(1 Point)

Answers

Answered by Arijit246

1

Answer:

n = 2

plug the value in formula we get

Required charge= 2 × 96487 Coulombs

= 192974 Coulombs

= 1.93 × 105 Coulombs

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