Chemistry, asked by vishusapkal2004, 1 month ago

How much charge is required for 1 mol of Al3 reduced to A12​

Answers

Answered by Anonymous
1

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Answered by sanjudnath
3

Answer:

Al3++3e−→Al

The reduction will require 3 Faraday of electricity or 3×96500=2.895×105C.

Cu2++2e−→Cu

The reduction will require 2 Faraday of electricity or 2×96500=1.93×105C.

MnO4−+5e−→Mn2+

The reduction will require 5 Faraday of electricity or 5×96500=4.825×105C.

Note: 1 mole of electron has a charge of 1 faraday.

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