How much charge is required for the reduction of 1 mole of zn by positive to zn?
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answer : 193000C
explanation : we have to find the amount of charge is required for the reduction of 1mole of Zn²+ to Zn.
see half reduction reaction...
Zn²+ + 2e- ⇔ Zn
here it is clear that, for one mole of reduction of Zn, 2moles of electron is required.
we know, 1 mole of electron is equivalent to 96500C charge.
so, 2 mole of electron ⇒2 × 96500C = 193000 C
hence, 193000C charge is required for the reduction of one mole of Zn²+ to Zn.
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