How much charge is said to be flowing if 5 A current passes through a wire every second?
Answers
Answer:
Given: Current I=5 A
To find: Number of electrons passing per second , for 5 A, n = ?
I=Qt
Charge of an electron
e=1.6×10−19 coulomb
Then 1 coulomb =11.6×10−19 electrons
i.e., 1 coulomb =6.25×1018 electrons
For 1 ampere current, no. of electrons will be 6.25×1018 electrons. For 5 ampere current, it is 5×6.25×1018 electrons
=3.125×1019 electrons
Alter:
No. of electrons passing per second , n =?
I=Qt
Where e→Charge of electron which is equal to 1.6×10−19C
Q is 'n' no of charges i.e., Q=ne
Here t = IS, ⇒I=net=1×te=5×11.6×10−19=51.6×1019
Number of Electrons,
n=3.125×1019 electrons
6
Explanation:
Current = Charge / time
Here current =5A, time=1 Second
So, total charge flown in 1 second= 5 coulomb
Charge on 1 electron =1.6*10^-19
Therefore no of charge particles= 5/(1.6*10^-19) = 3.125*10^19
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