Question

How much charge will appear on the plates if a capacitor has

capacitance of 177pF when p.d of 100 V is applied ?​

Answer 1

Answer:-

• Capacitance=C=177pF
• Voltage=100V
• Charge=Q=?

We know that

$\boxed{\sf Q=CV}$

$\\ \qquad\quad\sf\rightarrowtail Q=177\times 100$

$\\ \qquad\quad\sf\rightarrowtail Q=17700C$

$\\ \qquad\quad\sf\rightarrowtail Q=17.7\times 10^3C$

Note:-

SI unit of Charge is Columb(C)

Answer 2

Given:-

• Capacitance ,C = 177 pF
• Potential Difference ,V = 100 V

To Find:-

• How much charge will appear ,Q

Solution:-

According to the Question

It is given that ,

the plates if a capacitor has capacitance of 177pF when p.d of 100 V is applied . We have to calculate how much charge will appear on the plates .

Using Formula

• C = Q/V

where,

• C denote Capacitance
• Q denote amount of charge
• V denote Potential Difference

Substitute the value we get

$\longrightarrow$ 177 = Q/100

$\longrightarrow$ 177×100 = Q

$\longrightarrow$ Q = 177×100

$\longrightarrow$ Q = 17700 C

• Hence, the 17700 C charge will appear on the plates.

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