Question

How much cloth material will be required to cover 2 big domes each of

radius 3.5 metres? (Take = 22/7)​

Answer 1

$\Large{\underline{\underline{\tt{\purple{Hello !!}}}}}$

Given:

2 big domes each of radius 2.5 metres

To find:

How much cloth will be required to cover 2 big domes each of radius 2.5 metres?

Solution:

The radius of each of the dome, r = 2.5 meters

We know,

\boxed{\bold{Curved\:Surface\:Area \:of\:a\:hemisphere= 2\pi r^2}}

CurvedSurfaceAreaofahemisphere=2πr

2

Now,

The required area of the cloth to cover the 2 domes is,

= 2 × [Curved Surface Area of the Hemispherical dome]

$2 \times \: 2\pi \: r$

Substituting pi=22/7 and r= 2.5

$2 \times 2 \times \frac{22}{7} \times 2.5 \times 2.5$

$2 \times 2 \times \frac{22}{7} \times 6.25$

$\frac{550}{7}$

$= 78.57$

Therefore,

$78.57 \: \: {m}^{2} \: cloth \: will \: be \: required \: ..$

Brainliest .. !! ✨⚡❤

Answer 2

Given

• Two big domes needs to be covered.
• Radius of each ⇒ 3.5 metres

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To Find

• The amount of cloth required to cover the domes.

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Solution

We need to find the CSA of the domes to get the amount of cloth material required. First we will find for 1 and then with the value found we will find the second one too.

CSA of Hemisphere ⇒ 2πr²

('r' = Radius)

Radius ⇒ 3.5 meters

CSA of Hemisphere ⇒ $2\times \dfrac{22}{7}\times (3.5)^{2}$

CSA of Hemisphere ⇒ $2\times \dfrac{22}{7}\times 12.25$

CSA of Hemisphere ⇒ $2 \times \dfrac{269.5}{7}$

CSA of Hemisphere ⇒ 2 × 38.5

CSA of Hemisphere ⇒ 77 m²

Since we have to find the CSA for both we will multiply '2' to the obtained area.

CSA of Hemisphere ⇒ 77 × 2

CSA of Hemisphere ⇒ 154 m²

∴ 154 m² cloth would be required to cover 2 big domes each of radius 3.5 metres.

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