How much concentrated 6.0 M nitric acid is needed to prepare 100. mL of a 3.00 M solution?
A. 50 mL
B. 100 mL
C. 600 mL
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Answer:
The number of moles of nitric acid can be obtained by multiplying the molarity with volume
M×V=Moles of HNO
3
=
1000
250×2
=0.5
The mass of nitric acid can be obtained by multiplying the number of mols with molar mass and dividing with percentage concentration.
∴HNO 3 required =0.5×63×
70 /100
=45g
Thus 45.0 g conc. HNO 3 of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO 3
.
Hence, the correct option is A
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