Question

How much copper can be obtained from 100 g of copper sulphate ($CuSO_{4}$)?

Answer 1

1 mole of CuSO4 contains 1 mole of copper.

Molar mass of CuSO4

= Atomic mass of [Cu � 1 + S � 1 + O � 4 ]

=(63.5) + (32.00) + 4(16.0) = 63.5 + 32.0 + 64.0

= 159.5 g

Here molar mass of Cu is 159.5 g so that 159.5 of CuSO4 will produce 1 mole of Cu and mass of 1 mole of Cu is 63.5 g of copper.

So 100 g of CuSO4 will produce = \[\frac{{63.5 \times 100}}{{159.5}} = 39.8g\]

Answer : Amount of copper obtained from 100 g CuSO4 = 39.8 g

hope you understand

mark as brainliest plzzz

Answer 2

$CuSo_{4}$ describes 1 mole of copper sulphate which contains 1 mole of copper.

Now, molar mass of 1 mol copper sulphate is  

                                         $63.5+32+(4\times16)=159.5gm$  

where , molar mass of Cu is 63.5gm  

             molar mass of  S is 32gm  

     and, molar mass of O is 16 gm.

Therefore, 159.5 gm copper sulphate contains 63.5 gm copper.

                   100 g copper sulphate contains

$\frac{63.5}{159.5}\times100=39.81gm$ of copper.

39.81 gm copper can be obtained from 100g of copper sulphate.