Question

How much copper can be obtained from 100 gram of Copper Sulphate (CuSO4) ?​

Answer 1

Answer:

39.8g

Explanation:

1 mole of CuSO4 contains 1 mole of copper.

Molar mass of CuSO4

= Atomic mass of [Cu × 1 + S × 1 + O × 4 ]

=(63.5) + (32.00) + 4(16.0)

= 63.5 + 32.0 + 64.0

= 159.5 g

Here molar mass of Cu is 159.5 g , so that 159.5 of CuSO4 will produce 1 mole of Cu and mass of 1 mole of Cu is 63.5 g of copper.

So 100 g of CuSO4 will produce:

>> (63.5 * 100)/159.5

>> 39.8g

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Answer 2

Answer:

$\bf\mathcal{Answer}$

• 1 mole of copper sulphate contains 1 mole of Cu
• Molar mass of CuSO4

=159.5 g

• 159.5 g of CuSO4

• contains 63.5 g of Cu

Therefore,

The amount of Cu that can be obtained from 100g of CuSO4

:= 63.5×100/159.5

=39.81 g