how much copper can be obtained from 100 grams of copper sulphate
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the molar mass of CuSO4 (anhydrous) is 159.5 g
i.e mass of 1 mole of CuSO4 is 159.5 g
therefore 159.5 g (1 mole) of CuSO4 will produce 1 mole of Cu
And the mass of 1 mole of Cu is 63.5 g
therefore, 159.5 g of CuSO4 = 63.5 g of Cu
hence, 100g of CuSO4 = 63.5 * 100 g of Cu
159.5
=39.8g of Cu
Answer : Amt of Cu obtained from 100 g CuSO4 = 39.8 g.
i.e mass of 1 mole of CuSO4 is 159.5 g
therefore 159.5 g (1 mole) of CuSO4 will produce 1 mole of Cu
And the mass of 1 mole of Cu is 63.5 g
therefore, 159.5 g of CuSO4 = 63.5 g of Cu
hence, 100g of CuSO4 = 63.5 * 100 g of Cu
159.5
=39.8g of Cu
Answer : Amt of Cu obtained from 100 g CuSO4 = 39.8 g.
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