How much coulomb charge is required to reduce 1 mole of cr2o7-
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Question
How much coulomb charge is required to reduce 1 mole of Cr₂O₇²⁻ to Cr³⁺ ?
ANSWER
Cr₂O₇²⁻ + 14H⁺ + 6e⁻ ----> 2Cr³⁺ + 7H₂O
One mole Cr₂O₇²⁻ requires 6 moles of electrons for reduction
Thus, quantity of electricity required
= 6 × 96500
= 579000 Coulomb
FINAL RESULT = 5.79 × 10⁵ Coulomb
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