Question

how much cupric oxide is needed to decompose 3.4 gm NH3


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Answer 1

Answer:

23.7 g

Explanation:

The chemical equation for the given reaction is-

2NH3 + 3CuO «→» N2 + 3Cu + 3H2O

No. of moles of CuO required to react with 2 moles of NH3 = 3

Given mass of NH3 = 3.4 g

No. of moles of NH3 = 3.4/17 = 0.2 moles

So, Moles of CuO required = 3/2 × 0.2 = 0.3 moles

So, mass of CuO = 0.3 × 79 = 23.7 g

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