Question

How much current flows through a 3 kilo ohm resistor when a potential difference of 9 volt is applied across its ends

Answer 1

Answer:

Let us denote potential difference by V and Resistance by R.

Let the current going through the resistor be I (in Ampere)

By using Ohm’s law,V=I*R,here we need to use V,I,R in S.I. units

We are given V as 2 Volts and R as 1 Kohm i.e.1*(10^3) ohm.

substituting these values in equation of ohm’s law,we get

2=I*(10^3)

or I=2/(10^3) A ,where A denotes Ampere

I=2*(10^(-3)) A

I= 2 mA where m denotes milli

So,the current flowing through the resistor in above mentioned situation will be 2 mA