How much current is drawn by the primary of a transformer while steps down 220 V to 22 V to
operate a device with an impedance of 220 Ω?
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Answer :
Voltage of primary coil = 220V
Voltage of secondary coil = 22V
Impedance of device = 220Ω
We have to find current flow in primary coil
★ First of all we need to find power developed in secondary coil.
➝ P₂ = V₂²/R
➝ P₂ = 22²/220
➝ P₂ = 2.2 W
For an ideal transformer,
- Input power = Output power
∴ Input power will be also 2.2 W
We know that power is measured as the product of voltage and current.
Power developed in primary coil :
➝ P₁ = V₁ × I₁
➝ 2.2 = 220 × I₁
➝ I₁ = 0.01 A
∴ Current flow in primary coil will be 0.01A.
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