How much current is in a circuit that includes a 9-volt battery and a bulb with a resistance of 12 ohms?
Answers
Answered by
7
V=IR
V=9V
R=12ohm
I=?
from V=IR
9=I*12
I=9/12
I=3/4A
hence current is 3/4 ampere
hope this helps you
V=9V
R=12ohm
I=?
from V=IR
9=I*12
I=9/12
I=3/4A
hence current is 3/4 ampere
hope this helps you
Answered by
5
Hii...
➡️ As you know ,
V= iR
Where V = Potential difference = 9 v
i = Current = have to find
R = Resistance = 12 ohm
So, according to that formula
=> 9 = i × 12
=> i = 9/12 = 3/4 ampere current ...answer.
Hope this helps !
➡️ As you know ,
V= iR
Where V = Potential difference = 9 v
i = Current = have to find
R = Resistance = 12 ohm
So, according to that formula
=> 9 = i × 12
=> i = 9/12 = 3/4 ampere current ...answer.
Hope this helps !
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