how much current is passed through cuso4 solution ,0.6amp.Current is passed for 7 minutes?
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Answer:
Explanation:
The question that you asked must be how much copper will be deposited at the cathode.
Since, current is already given, and ampere is defined as C/sec.
Thus,
Charge for 0.6amp
0.6amp = 0.6C/s*7*60 = 252C
Thus, number of moles of copper formed
To find that we need the equation,
Q=nzF
Where z is the number of electrons in the half cell here which is 2 .
n is the number of moles.
And F is the faradays constant 96500.
Hence,
n=Q/zF
n=252/2*96500
n=0.001
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