Question

How much current will an electric bulb draw from a 220 V source, if the

resistance of the bulb filament is 1200 Ω? (b) How much current will an electric

heater coil draw from a 220 V source, if the resistance of the heater coil is 100 Ω?​

Answer 1

Answer:

0.1833A,2.2A

Explanation:

a)V=220V

R=1200 ohm

R=V/I

I=V/R

=220/1200

=0.1833A

b)same as the above

I=220/100

=2.2A

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Answer 2

$\huge {\underline{\pink{Given:-}}}$

Potential Difference ,V = 220V

Resistance ,R = 1200Ω

Resistance of Heater Coil = 100Ω

$\huge {\underline{\blue{To Find:-}}}$

Current in both Case ,I

$\huge {\underline{\green{Solution:-}}}$

Using Ohm's Law

• V = IR

Where,

V is the Voltage

I is the Current

R is the resistance.

For Bulb

V = IR

Substitute the value we get

➺ 220 = I × 1200

➺ I = $\frac{220}{1200}$

→ I = 0.18 A

Therefore, the current flow in the bulb is 0.18 Ampere.

For Electric Heater

V = IR

➺ I = $\frac{V}{R}$

Substitute the value we get

➺ I = $\frac{220}{100}$

➺ I = 2.2 A

Therefore, the current flow in the bulb is 2.2 Ampere.