Question

How much current will an electric bulb draw from a 220v source if resistance of bulb filament is 1200

Answer 1

${\mathfrak{\green{\underline{\underline{Solution:-}}}}}$

Given:

V = 220 V  

R = 1200 Ohm  

I = ?

By using Ohm's law.

so, I = V/R  

     = 220/1200

     = 0.183 Ampere

I = 0.18 Ampere

Answer 2

Answer:

0.18 A

Explanation:

Given :

potential difference = 220 V

Resistance ( R ) = 1200 Ω

current ( I ) = ?

We have ohm's law  that state at constant temperature current flowing in conductor is directly proportional of its potential difference across two ends.

V = I R

Put the values here

220 = 1200 × I

$\large I=\dfrac{220}{1200} \ A\\\\\\\large I=\dfrac{11}{60} \ A\\\\\\\large I=0.18 \ A$

Hence 0.18 A current will drawn from an electric bulb.