Question

How much current will an electric bulb draw from a 220V source, if resistance of the filament of a bulb is 800 Ω​

Answer 1

Answer:

the answer will be 0.275

Explanation:

the formula of current is

I=q/t

here there is no any charge given so we use another formula of potentiol difference.

V=IR

here V=220V

and R=800

use formula

V=IR

800=220×I

800/220=I

o.275=I

thus the answer will be 0.275A

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Answer 2

Given:

• Voltage = 220V
• Resistance= 800Ω

Solution:

According to the Ohm's law:

$\boxed{\red{I = \frac{V}{R}}}$

$\implies{I = \frac{220}{800}} A$

$\bold{\red{\implies{I = 0.275 \: A}}}$

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