How much current will an electric bulb draw from a 420 V source. If the resistance bulb filament is 1200 ohm.
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given ,
resistance = 1200 ohm (r)
voltage source = 420 V (v)
we know that,
v=Ir
I=v/r
=420/1200
=210/600
=105/300
=21/60
=0.35 ampere
Answered by
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I= V/R
I = 420 /1200= 21/60=7/20=0.35 AMPHERES
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