Question

How much current will an electric bulb
drow from a 220v Source if the resistance
the bulb & filament is 12002/220 V​

Answer 1

Answer:

I=V/R

I=220/1200

I=11/60

Answer 2

$\huge {\underline{\pink{Given:-}}}$

Potential Difference ,V = 220V

Resistance ,R = 1200Ω

Resistance of Heater Coil = 100Ω

$\huge {\underline{\blue{To Find:-}}}$

Current in both Case ,I

$\huge {\underline{\green{Solution:-}}}$

Using Ohm's Law

• V = IR

Where,

V is the Voltage

I is the Current

R is the resistance.

For Bulb

V = IR

Substitute the value we get

➺ 220 = I × 1200

➺ I = $\frac{220}{1200}$

→ I = 0.18 A

Therefore, the current flow in the bulb is 0.18 Ampere.

For Electric Heater

V = IR

➺ I = $\frac{V}{R}$

Substitute the value we get

➺ I = $\frac{220}{100}$

➺ I = 2.2 A

Therefore, the current flow in the bulb is 2.2 Ampere.