Question

How much current will an electric heater coil draw from a 220v source if the resistence of the/heater coil is 100?

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Current(I)=2.2A }}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Voltage (V) = 220 volt

• Resistance (R) = 100 ohm

$\large\underline\pink{\sf To\:Find: }$

• Current (i) = ?

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According to Ohm's Law :-

${\boxed{\sf Voltage(V)=Current (I)×Resistance(R) }}$

$\large\implies{\sf 220=I×100 }$

$\large\implies{\sf I=\frac{220}{100} }$

$\large\implies{\sf I=2.2A}$

$\large\red{\boxed{\sf Current(I)=2.2A }}$

Answer 2

$\huge {\underline{\pink{Given:-}}}$

Potential Difference ,V = 220V

Resistance ,R = 1200Ω

Resistance of Heater Coil = 100Ω

$\huge {\underline{\blue{To Find:-}}}$

Current in both Case ,I

$\huge {\underline{\green{Solution:-}}}$

Using Ohm's Law

• V = IR

Where,

V is the Voltage

I is the Current

R is the resistance.

For Bulb

V = IR

Substitute the value we get

➺ 220 = I × 1200

➺ I = $\frac{220}{1200}$

→ I = 0.18 A

Therefore, the current flow in the bulb is 0.18 Ampere.

For Electric Heater

V = IR

➺ I = $\frac{V}{R}$

Substitute the value we get

➺ I = $\frac{220}{100}$

➺ I = 2.2 A

Therefore, the current flow in the bulb is 2.2 Ampere.