Question

how much distance an object will cover in 10 sec if its acceleration is 20 m/s^2​

Answer 1

Step-by-step explanation:

First, know that what I’m putting here is only relevant if our acceleration vector is pointing in the same direction the whole time. Basically, if you’re swinging the object around on a string or pushing it from an oblique angle, or doing something else to vary the direction of the acceleration, the results will be very different because then you deal with 2d or 3d movement instead of just the 1d stuff.

v=∫10dt

v=10t+C

x=∫vdt

x=∫10t+Cdt

x=10t2+Ct+D

Yes, I used the generic C and D, instead of V0 and X0

What we care about is the quantity Δx=x−D

(x−D)=10t2+Ct

So the answer is, it depends on the initial velocity, C.

Hope this helps, and all the best!