How much distance is travelled
by minute hand
a clock in one complete revolution if length of
a minute, hand is 14cm?
Answers
Answer:
Minute hand completes full circle degree in 60 minutes.
Angle swept by minute in 60 minutes =360°
Angle swept by the minute hand in 15 minutes =
60
360°×15=90°
Therefore,
θ=90°
Length of minute hand =r=14cm
Area swept by minute hand in 15 minutes = Area of sector
As we know that area of sector is given as-
A=
360°θ×πr
2
Therefor,
Area swept by the minute hand in 15 minutes =
360°
90°×( 722×(14) 2 )= 4 ×616=154cm
Hence the area swept by the minute hand in 15 minutes is 154cm
Hence the correct answer is 154cm
Minute hand completes full circle degree in 60 minutes.
Angle swept by minute in 60 minutes =360°
Angle swept by the minute hand in 15 minutes =
60
360° ×15=90°
Therefore,
θ=90°
Length of minute hand =r=14cm
Area swept by minute hand in 15 minutes = Area of sector
As we know that area of sector is given as-
A=
360°θ ×πr
Therefor,
Area swept by the minute hand in 15 minutes =
360°
90° ×( 7*22×(14) 2 )= 41 ×616=154cm
Hence the area swept by the minute hand in 15 minutes is 154cm
Hence the correct answer is 154cm