how much distance will be travelled by dinesh if he would have returned to place A through place D
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Answer:
Distance travelled by Dinesh = AB + BC = 7.5+12=19.5
Distance travelled by Ayub = AD + DC = 9.3+11.8=21.1
Ayub travelled more than Dinesh .
difference=21.1-19.5=1.6
He travelled 1.6 km more than Dinesh
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