Math, asked by priyasujesth, 10 months ago

How much does 12a2 +19ab -40 exceed 3a3

-5a2 +12ab -11?

Answers

Answered by zahaansajid

0

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Here's your answer

To find out how much it exceeds we have to subtract

p(x) = 12a²+19ab-40 from

g(x) = 3a³-5a²+12ab-11

Hence

g(x) - p(x) => 3a³-5a²+12ab-11 - 12a²-19ab+40

=> 3a³-17a²-7ab+29

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