Question

How much does 2a²-5a+4 exceed 3a³-5a² +7a-9?​

Answer 1

Answer:

2a²-5a+4 exceed 3a³-5a² +7a-9 by -3a³ + 7a² - 12a + 13

Step-by-step explanation:

to find a number that exceeds another no we need to subtract both of them

(2a² - 5a + 4) - ( 3a³ - 5a² + 7a - 9)

=2a² - 5a + 4 - 3a³ +5a² - 7a + 9

= -3a³ + 2a² + 5a² - 5a -7a +4 + 9

= -3a³ + 7a² - 12a + 13

Hope it helps!!!!!