Question

how much does -2a²+6b+9 exceeds 4a²-2b+7

Answer 1

Answer:

please mark me as brainliest please

Step-by-step explanation:

Let f(x)=ax2+bx+c, where a,b,c∈R, a≠0. Suppose ... 39605039. 55. 1.3 K. 6:41. Let `f(x) =ax^2 + bx+ c AA a,. play. 89414. 2.5 K .

Answer 2

Step-by-step explanation:

$- 2a {}^{2} + 6b + 9 \: \: - (4a {}^{2} - 2b + 7) \\ = - 2a {}^{2} + 6b + 9 - 4a {}^{2} + 2b - 7 \\ - 6a {}^{2} + 8b + 2$