How much does 2x²–5x + 4 exceed 3x® – 5x² + 7x -9?
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Step-by-step explanation:
(2x^2 + 3x + 4)+ (5x^2-8x - 5 )+ (2x^2+7x - 6)
2x^2 + 3x + 4 + 5x^2-8x - 5+2x^2 + 7x -6
(2x^2 + 5x^2 + 2x^2)+(3x -8x +7x)+(4-5-6)
9x^2 + 2x -7
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