Math, asked by girlreacting, 6 months ago

how much does 2x²+5x-4 exceed 3x³+7x-9

Answers

Answered by ayushisagar1000

1

Answer:

Here 2x²+5x-4 exceed 3x³+7x-9

we subtract 2x²+5x-4 from 3x³+7x-9

Let's solve

2x²+5x-4-(3x³+7x-9 )

By opening bracket we get

2x²+5x-4-3x³-7x+9

= 2x²+5x-7x-4+9-3x³

=2x²-2x+5-3x³

Ans = -3x³+2x²-2x+5

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