How much does 3x² - 5x + 2 exceed x - x² + 4x - 1 ?
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3x^2 - 5x + 6 - x^3 + x^2 - 4x + 1 = - x^3 + 4x^2 - 9x + 7. Therefore 3x²-5x+6 exceeds x³-x²+4x-1 by - x^3 + 4x^2 - 9x + 7
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