Question

how much does 4 exceed 2x-3y-4?

Answer 1

Step-by-step explanation:

Answer:

1 will exceed 2x-3y-4 by 3y-2x+5.

Step-by-step explanation:

Given the value

2x - 3y - 42x−3y−4

we have to find the value for which the number 1 exceeds from the given value i.e 2x - 3y - 4

Let A=2x - 3y - 4

Now let B be the value from which 1 exceeds from A i.e

1 exceeds A=2x-3y-4 by:

B=1-AB=1−A

=1-(2x-3y-4)=1−(2x−3y−4)

Opening the brackets we get 1-2x+3y+4.

Combining like terms:

1+4-2x+3y1+4−2x+3y

= 5 - 2x + 3y=5−2x+3y

i.e 3y -2x+5

Therefore 1 will exceed 2x-3y-4 by 3y-2x+5.