how much does 5y²-5/7 exceed 2x²-5/7y pt
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Answered by
1
Explanation:
Solution
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Let the ellipse equation be
a
2
x
2
+
b
2
y
2
=1
e=
5
2
or,
a
2
a
2
−b
2
=
5
2
Squaring both sides,
5(a
2
−b
2
)=2a
2
or,a
2
=
3
5
b
2
And the ellipse passes through the point (−3,1)
a
2
9
+
b
2
1
=1
9b
2
+a
2
=a
2
b
2
9b
2
+
3
5
b
2
=
3
5
b
4
3
32
=
3
5
b
2
b
2
=
5
32
a
2
=
3
32
Equation :
32
3x
2
+
32
5y
2
=1
⟹3x
2
+5y
2
=32
Answered by
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