Math, asked by mmmangla77p8pyv2, 9 months ago

How much does 93p²-55p+4 exceed 13p³-5p²+17p-90?

answer is -13p³+98p²-72p+94
but how please explain. I will mark you brain list!! ​

Answers

Answered by Nabh2006
4

to find,

13p^2-5p^2+17p-90+x=93p^2-55p^2+4

we need to find x in the above equation

8p^2+17p-90+x=38p^2+4

x=38p^2+4-(8p^2+17p-90)

x=38p^2+4-8p^2-17p+90)

x=30p^2-17p+94

hence shown

Similar questions