how much does 9a²+7a-2 exceed 2a²+4a²+3a+1
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Answered by
9
Answer:
(9a²+7a-2)-(2a³+4a²+3a+1)
9a²+7a-2-2a³-4a²-3a-1
(-2a³9a²-4a²)(7a-3a)(-2-1)
-2a³+5a²+4a-3
Step-by-step explanation:
Answered by
2
Answer:
3 is right answer
Step-by-step explanation:
Hope itz helps u
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