How much does 9x 2 + 7x – 2 exceed to 4x 2 + 3x + 1?
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Answer:
9x^2 +7x-2 exceed 2x^3+4x^2+3x+1 by -2x^3+3x^2×4x-3
Step-by-step explanation:
9x^2 +7x-2{2x^3+4x^2+3x+1}
9x^2 +7x-2-2x^3-4x^2-3x-1
-2x^3+9x^2-4x^2+7x-3x-1-2
-2x^3+3x^2×4x-3
hope it's helpful
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