Question

How much does 9x 2 + 7x – 2 exceed to 4x 2 + 3x + 1?

Answer 1

Answer:

5x2+4x-3

Step-by-step explanation:

To find exceed we need to subtract the smaller one from the bigger one.

Step 1:9x2+7x-2

-(4x2+3x+1).

Step 2:9x2+7x-2

-4x2-3x-1

Step 3: 9x2-4x2=5x2

7x-3x=4x

-2-1=-3

so Answer becomes 5x2+4x-3